Question

A solid shaft of 20mm radius is transmitting 2.5 kW with frequency of 50 Hz calculate maximum shear stress

Answer 1

Dear Student,

◆ Answer -

Shear stress = 5.071×10^6 Pa

● Explanation -

# Given -

r = 20/2 = 10 mm = 0.01 m

P = 2.5 kW = 2.5×10^3 W

f = 50 Hz

# Solution -

Shear stress is given by -

Shear stress = 2τ / πr³

Shear stress = 2 (P/2πf) / πr³

Shear stress = P / π²r³f

Substitute values,

Shear stress = 2.5×10^3 / (3.14^2 × 0.01^3 × 50)

Shear stress = 5.071×10^6 Pa

Thanks dear. Hope this helps you...

Answer 2

Answer:

0.633 Mpa

Explanation:

Given: -  

r = 20 = 20 mm = 0.02 m  

P = 2.5 kW = 2.5×10^3 W  

f = 50 Hz  

Solution: -  

Shear stress is given by -  

Shear stress = 2τ / πr³  

Shear stress = 2 (P/2πf) / πr³  

Shear stress = P / π²r³f  

Shear stress = 2.5×10^3 / (3.14^2 × 0.02^3 × 50)  

Shear stress = 0.633 MPa