A solid solution of a sphere is melted of a radius 'r' is recast into the shape of solid cone of height 'r' . Then what is the radius of the base of cone?
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The Radius of the base of the cone is 2r.
Step-by-step explanation:
Given :
A solid sphere of radius = r
solid cone of height,h = r
Let the radius of the cone be ‘R’
Volume of sphere = Volume of cone
[Sphere is melted and recast in the shape of cone]
4/3 πr³ = ⅓ πR²h
4r³ = R²(r)
4r³/r = R²
4r² = R²
R = √(4r²)
R = 2r
Radius of the cone = 2r
Hence, the Radius of the cone is 2r.
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