Question

a solid sphere is melted and cast into the shape of a solid cone of height radius of the base of the cone​

Answer 1

Step-by-step explanation:

Let the radius of the cone = R

and Height of a cone = r [Given]

Volume of cone =

1 \div 3\pi {}^{2} h

Now,

Volume of sphere = Volume of cone

= )\frac{4}{3} \pi ^{3} = \frac{1}{3} ^{2} h \\ = ) \: 4r^{2} = r^{2} (r) \\ = )r = 2

thus,the radius of the base of cone =2r

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