A solid sphere of diameter 6 cm is dropped in a right circular cylindrical vessel partly filled with water. The diameter of the cylindrical vessel is 12 cm. If the sphere is completely submerged in water, by how much will the level of water rise in the cylindrical vessel?
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Answer:
1 cm
Step-by-step explanation:
Volume of Sphere = (4/3)πR³
Diameter = 6cm => Radius = 3 cm
=> Volume of Sphere = (4/3)π3³ = 36π cm³
=> Volume of water in vessel = 36π cm³
Volume of water rise in Cylinder = πR²h ( where h = rise in water)
Diameter = 12 cm => Radius = 6cm
Volume of water rise in Cylinder = π6²h = 36πhcm³
36πh = 36π
=> h = 1
=> height = 1 cm
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