A solid sphere of mass m and radius R is on a rough surface as shown in figure. Two forces having magnitude 2F and F are applied as shown. If the sphere
performs pure rolling along right direction, then frictional force acting on the sphere is
Answers
The friction force acting on the body is in forward direction
Explanation:
Since the sphere of mass m and radius R performs pure rolling along the right direction
Therefore, the tendency of the sphere slipping will be in the left direction i.e. in the backwards direction
We know that on any body, friction force acts in the direction opposite to the direction of tendency of slipping of body
Therefore, the friction force on the solid sphere will be acting in the right direction i.e. in the forward direction
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Q: A particle of mass m is kept on the top of a smooth sphere of radius R. It is given a sharp impulse which imparts it a horizontal speed v (a) Find the normal force between the sphere and the particle just after the impulse? (b) What should be the minimum value of v for which the particle does not slip on the sphere (c) Assuming the velocity v to be half the minimum calculated in part (b) find the angle made by the radius through the particle with the vertical when it leaves the sphere ?
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Answer:
Anti-clockwise direction
Explanation:
Frictional force acting on the sphere would be in anti-clockwise direction or towards left.
Frictional force is always opposing the motion and the direction of motion. Now we have two forces, 2F and F. Since 2F is larger than F by magnitude, hence 2F will dominate and would make the ball move towards right or clockwise direction. To oppose this, frictional force would be in anticlockwise direction for this rolling motion