A solid sphere of radius 3 centimetre is melted and recast into small spherical ball of diameter 0.6 m find the number of calls
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radius if big sphere = 3cm
new sphere diameter =.6cm
radius of new sphere=.3cm
Let number of new spheres = x
so
![\frac{4}{3} (\pi {R}^{3} ) = x \times \frac{4}{3} (\pi {r}^{3} ) \\ \frac{3 \times 3 \times 3}{.3 \times .3 \times .3} = x \\ 1000 = x \frac{4}{3} (\pi {R}^{3} ) = x \times \frac{4}{3} (\pi {r}^{3} ) \\ \frac{3 \times 3 \times 3}{.3 \times .3 \times .3} = x \\ 1000 = x](https://tex.z-dn.net/?f=+%5Cfrac%7B4%7D%7B3%7D+%28%5Cpi+%7BR%7D%5E%7B3%7D+%29+%3D+x+%5Ctimes+%5Cfrac%7B4%7D%7B3%7D+%28%5Cpi+%7Br%7D%5E%7B3%7D+%29+%5C%5C+%5Cfrac%7B3+%5Ctimes+3+%5Ctimes+3%7D%7B.3+%5Ctimes+.3+%5Ctimes+.3%7D+%3D+x+%5C%5C+1000+%3D+x)
number of balls = 1000
new sphere diameter =.6cm
radius of new sphere=.3cm
Let number of new spheres = x
so
number of balls = 1000
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Answer:
Let the radius of solid sphere be r₁ and for spherical ball be r₂ .
Now :
Number of ball = Volume of solid sphere / volume of spherical ball .
= 4 / 3 π r₁³ / 4 / 3 π r₂³
= 4 / 3 π × 3 × 3 × 3 / 4 / 3 π × 0.3 × 0.3 × 0.3
= 3 × 3 × 3 / 0.3 × 0.3 × 0.3
= 1000 .
Therefore , Number of balls is 1000 .
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