Question

A solid sphere of radius 3 is melted and reformed by

stretching it into a cylindrical shaped wire of length 9.

Find the radius of the wire.
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Answer 1

Answer:

Answer is 2.

volume of sphere = 4/3pi r^3

= 4/3×3×3×3×pi

= 4×9pi

=36pi

Volume of cylinder = pi r^2 h

= pi r^2 ×9

both volume are same

So,

36 pi = pi r^2 9

36=r^2 9

r^2 = 36/9

r=root4

=2