A solid sphere of radius 6cm is melted into a hollow cylinder of uniform thickness. If the external radius of the base of the cylinder is 4cm and its height is 72cm, find the uniform thickness.
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The radius of the solid sphere = 6cm
The outer radius of the cylinder formed =4cm
The height of the cylinder =72cm
Let the internal radius be x cm
So, Volume of sphere =Volume of cylinder formed
4/3*22/7*6*6*6=22/7*(R^2-r^2)*72
4/3*216=(16-r^2)*72
4=(16-r^2)
r^2=16-4
r^2=12
r = 3.46cm
The uniform thickness is R-r 4-3.46= 0.54cm 0.
Hope this will help u!
The outer radius of the cylinder formed =4cm
The height of the cylinder =72cm
Let the internal radius be x cm
So, Volume of sphere =Volume of cylinder formed
4/3*22/7*6*6*6=22/7*(R^2-r^2)*72
4/3*216=(16-r^2)*72
4=(16-r^2)
r^2=16-4
r^2=12
r = 3.46cm
The uniform thickness is R-r 4-3.46= 0.54cm 0.
Hope this will help u!
Anonymous:
little bit same....only the decimal digits r varying...
the answer is 0.54cm
Yeah actually r=3.46 thus uniform radius will be (R-r) therefore , 4-3.46= 0.58
Thanks again!
Yups
so mark it brainliest!!!plz
Ans = 0.54* :-)
Yups...
Yeah but to mark it as brainliest someone else has to also ans
Then afterwards plz...mark it
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hope it helps you!!
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