Question

A solid sphere with a cavity just floats in water. The volume of sphere is v and relative density of material of sphere is 2. Then the volume of cavity is

Answer 1

Answer:

4/3 $\pi r^{3}$ =4/3*22/7*7 =88/3cm$cm^{3}$

Explanation:

Answer 2

A solid sphere with a cavity just floats in water. The volume of sphere is v and relative density of material of sphere is 2. Then the volume of cavity is.

relative density of material of sphere = 2

so, density of material of sphere = 2g/cm³

a/c to question,

solid sphere with a cavity just floats in water.

Let volume of cavity is x

now, $(v-x)\rho_sg=v\rho_wg$

or, (v - x) × 2g/cm³ = v × 1g/cm³

or, (v - x) × 2 = v

or, v - x = v/2

or, x = v/2

hence, volume of sphere is v/2