Question

A solid sphere with radius
0.4m carries a net charge of 0.25 nC.
The magnitude of electric field at a
distance 0.1m inside the surface of
sphere
zero
9 N/C
18 N/C
0.25 N/C
​

Answer 1

Answer:

The magnitude of the electric field will be 0.9×10³N/C.

Explanation:

The electric field for a point inside the solid sphere is calculated as,

$E=\frac{kQr}{r_0^3}$       (1)

Where,

E=electric filed inside the solid sphere

k=coulomb's constant=9×10⁹Nm²/C²

Q=net charge on the sphere

r=radius of the sphere

r₀=point inside the sphere

From the question we have,

The radius of the sphere(r)=0.4m

The net charge on the sphere(Q)=0.25nC=0.25×10⁻⁹C

The point inside the sphere(r₀)=0.1m

By placing all the required entities in equation (1) we get;

$E=\frac{9\times 10^9\times 0.25\times 10^-^9\times 0.4}{(0.1)^3}$

$E=0.9\times 10^3\ N/C$

So, the magnitude of the electric field will be 0.9×10³N/C.

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