Question

A solid weighs 15 Newton in air 10 Newton in water then the relative density of liquid is (weight of liquid is 25 by 3)​

Answer 1

Answer: 3

Explanation:

rd=density air/air-water

15/15-10=3

Answer 2

When a solid weighs 15 N in air and 10 N in water, Then the relative density of liquid is 3.

Explanation:

Relative density is the ratio between the density of a substance and the density of Water

formula for Relative density

R . D =    $\frac{weight of solid in air}{Weight of solid in air - weight of solid in water}$

R.D =  W / W-W⁻

where W = Weight of solid in air

           W⁻ = weight of solid in water

   R.D = 15 /15-10 = 15 /5 = 3

Relative density of liquid is 3