A solid weighs 75 g in air and 55.6 g in water. Find the relative density.
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the relative density is 123g
aadhisankaran35:
how
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Archimedes: When a body is immersed in a fluid it undergoes a loss in mass equivalent to the mass of fluid displaced .
Loss in mass = 75g - 55.6= 19.4g H2O displaced
Density of water = 1g/mL
Therefore the object displaced 19.4mL of water = volume of the object .
Relative density when kept in water = mass / volume
Relative density =55.6 / 19.6mL
Relative density = 2.836/mL
Loss in mass = 75g - 55.6= 19.4g H2O displaced
Density of water = 1g/mL
Therefore the object displaced 19.4mL of water = volume of the object .
Relative density when kept in water = mass / volume
Relative density =55.6 / 19.6mL
Relative density = 2.836/mL
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