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Yashyadavsingh:
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In triangle ABC
angle A + angle B + angle C = 180°
=> 76° + 52° + angle C = 180°
=> angle C = 180° - 128°
=> angle C = 52°
angle OBC = 1/2 angle B
=> angle OBC = 26°
angle OCB = 1/2 angle C
=> OCB = 26°
In triangle OBC,
angle O + angle OCB + angle OBC = 180°
=> Y + 26° + 26° = 180°
=> y + 52° = 180°
=> y = 180° - 52°
=> y = 128°
Hope that it will help you.
angle A + angle B + angle C = 180°
=> 76° + 52° + angle C = 180°
=> angle C = 180° - 128°
=> angle C = 52°
angle OBC = 1/2 angle B
=> angle OBC = 26°
angle OCB = 1/2 angle C
=> OCB = 26°
In triangle OBC,
angle O + angle OCB + angle OBC = 180°
=> Y + 26° + 26° = 180°
=> y + 52° = 180°
=> y = 180° - 52°
=> y = 128°
Hope that it will help you.
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