a solid weighs 75g in air and 55.6g in water . Find the relative density
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Answered by
62
relative density of an object = density of object/density of water
but r .d of object =75-55.6
=19.4
density of object/density of water =75/19.4
= 3.86
but r .d of object =75-55.6
=19.4
density of object/density of water =75/19.4
= 3.86
sweety70:
whats r.d....??
Answered by
16
hey mate...
Solid weighs 75 gms in air, and 55.6 gms in water.
So, difference in weight = buoyant force
19.6= weight of liquid displaced.
19.6/g=mass of liquid
=2 = mass of liquid
Since the liquid is water and the density 1 kg/m3, the volume of the liquid displaced=volume of the solid = 2 m3
SO, density = 75/1000/2
= 0.0375
and it will float because its density is less that of water.
Solid weighs 75 gms in air, and 55.6 gms in water.
So, difference in weight = buoyant force
19.6= weight of liquid displaced.
19.6/g=mass of liquid
=2 = mass of liquid
Since the liquid is water and the density 1 kg/m3, the volume of the liquid displaced=volume of the solid = 2 m3
SO, density = 75/1000/2
= 0.0375
and it will float because its density is less that of water.
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