Question

A solid wooden toy in the shape of right circular cone mounted on w hemisphere . the radius of the hemisphere is 4.2 cm and total height of the toy is 10.2 cm then total volume of toy is

Answer 1

hii mate!!

The volume of a sphere of radius r is given by 
V = (4/3)πr³ 
So the volume of a hemisphere will be half of that, which is (2/3)πr³ 

The volume of a cone of base radius r and height h is: 
V = (1/3)πr²h 

We are told that r = 4.2 cm 

The total height of the toy is made up of (the height of the cone) + (height of hemisphere) 
So the height of the cone = 10.2 - 4.2 = 6 cm 

So the volume of the toy = (volume of hemisphere + volume of cone) 
= (2/3)π * 4.2³ + (1/3)π * 4.2² * 6 
= 155.2 cm³ + 110.8 cm³ 
= 266 cm³

hope it helps !!☺☺

Answer 2

Hey! ! !

Solution :-

☆ V = (4/3)πr³ 
So the volume of a hemisphere will be half of that, which is (2/3)πr³ 

The volume of a cone of base radius r and height h is: 
V = (1/3)πr²h 

We are told that r = 4.2 cm 

The total height of the toy is made up of (the height of the cone) + (height of hemisphere) 
So the height of the cone = 10.2 - 4.2 = 6 cm 

So the volume of the toy = (volume of hemisphere + volume of cone) 
= (2/3)π * 4.2³ + (1/3)π * 4.2² * 6 
= 155.2 cm³ + 110.8 cm³ 
= 266 ans

☆ ☆ ☆ Hop its helpful ☆ ☆ ☆

☆ Regards :- ♡♡《 Nitish kr singh 》♡♡