A solid wooden toy is in the shape of a right circular cone mounted on a hemisphere. if the radius of the hemisphere is 4.2 cm and the total height of the toy is 10.2 cm, find the volume of the wooden toy?
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257
V = (4/3)πr³
So the volume of a hemisphere will be half of that, which is (2/3)πr³
The volume of a cone of base radius r and height h is:
V = (1/3)πr²h
We are told that r = 4.2 cm
The total height of the toy is made up of (the height of the cone) + (height of hemisphere)
So the height of the cone = 10.2 - 4.2 = 6 cm
So the volume of the toy = (volume of hemisphere + volume of cone)
= (2/3)π * 4.2³ + (1/3)π * 4.2² * 6
= 155.2 cm³ + 110.8 cm³
= 266 cm³
If this is not clear, Please refer the attachment ;)
Hope This Helps :)
So the volume of a hemisphere will be half of that, which is (2/3)πr³
The volume of a cone of base radius r and height h is:
V = (1/3)πr²h
We are told that r = 4.2 cm
The total height of the toy is made up of (the height of the cone) + (height of hemisphere)
So the height of the cone = 10.2 - 4.2 = 6 cm
So the volume of the toy = (volume of hemisphere + volume of cone)
= (2/3)π * 4.2³ + (1/3)π * 4.2² * 6
= 155.2 cm³ + 110.8 cm³
= 266 cm³
If this is not clear, Please refer the attachment ;)
Hope This Helps :)
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Answered by
108
Hi dear here is your answer.
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