Question

A solid X insoluble in water weight 180 gm in air and 150 GM in water . What is the relative density of X

Answer 1

Relative Density = W air /  W air - W water

= 180 / (180-150)

= 180/30

=6

Answer 2

Answer: The correct answer is 6.

Explanation:

The expression for the relative density is as follows;

$Relative density = \frac{w_{air}}{(W_{air}-W_{water})}$

Here, $W_{air}$  is the weight in air and  $W_{water}$ .

It is given in the problem that A solid X insoluble in water weight 180 gm in air and 150 gm in water.

Put $w_{air}= 180 g$ and $w_{air}= 150 g$ .

$Relative density = \frac{180}{(180-150)}$

$Relative density = \frac{180}{(180-150)}$

$Relative density =6$

Therefore, the relative density of X is 6.