given that hcf ( 2520 ,6600 )= 40 lcm (2520 , 6600 )=252 * k then find the value of k
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Answered by
34
!!
We have ,
HCF ( 2520 , 6600 ) = 40
LCM ( 2520 , 6600 ) = 252 × k
As we know ,
HCF ( a , b ) × LCM ( a , b ) = 2520 × 6600
HCF ( 2520 , 6600 ) × LCM ( 2520 , 6600 ) = 2520 × 6600
40 × ( 252 × k ) = 2520 × 6600
Therefore, the value of k is 1650.
We have ,
HCF ( 2520 , 6600 ) = 40
LCM ( 2520 , 6600 ) = 252 × k
As we know ,
HCF ( a , b ) × LCM ( a , b ) = 2520 × 6600
HCF ( 2520 , 6600 ) × LCM ( 2520 , 6600 ) = 2520 × 6600
40 × ( 252 × k ) = 2520 × 6600
Therefore, the value of k is 1650.
Answered by
5
Answer:
k= 1650
Step-by-step explanation:
given, LCM= 252*k
HCF= 40
a= 2520
b= 6600
HCF*LCM= a*b
40*252*k= 2520*6600
k= 2520*6600/ 40*252
k= 1650
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