A solod sphere of radius r made of a material of bulk modulis k
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Hi
Here is your answer,
When mass M is placed on the piston, the excess pressure , p = Mg/A. As this pressure is equally applicable from all the direction on the sphere , hence there will be become in volume due to decrease in radius of sphere.
Volume of the sphere, V = 4/3 πR³
Differentiating it, we get
Δt = 4/3 π(3 R²)ΔR = 4πR² ΔR
∴ ΔV/V = 4/3R² ΔR/4/3 πR³ = 3ΔR/ R
We know that, B = P/dV/V = Mg/A/3ΔR/R
or, ΔR/R = Mg/3BA
Hope it helps you !
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