A thin rod of length l and mass m oscillating about its one end
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The time period of oscillation of a uniform rod with length l pivoted at one end is
2πl2g−−−√2πlg−−√2π2l3g−−−√2πl3g−−−√
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Solution :
For a rigid body oscillating about horizontal axis passing through the point O the time period is given by
T=2πImg(OG)−−−−−−−√
Where I moment of rigid body and OG is the distance of the point of pivot to the centre of gravity G and I is the moment of inertia of the rod.
I=13me2
OG=l2
T=2π13ml2mgl2−−−−−−⎷
=2π2l3g−−−√
Answer : 2π2l3g−−−√
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