Question

A solid shell loses half of its weight in water.Relative density of shell is 5.0 what fraction of its volume is hollow

Answer 1

Answer:

The weight of the ball= W = ρ V

The upward force=U  =the weight of the displaced water

so,

U = ρwater V 

given: U = W/2.

Therefore 

ρwater V = 1/2 x ρsolid Vsolid 

Vsolid / V = 1/2 x  ρwater/ρsolid 

also;

ρ water/ρ solid = 1/5 

Hence 

Vsolid / V = 1/10