A solute a has 2 is to 3 molar ratio of toluene to benzene the vapour pressure of benzene and toluene is 25 degree centigrade and 9528 the mole fraction of toluene vapour is
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The mole fraction of toluene in the vapour = 0.548
Explanation:
Given: A solute a has 2:3 molar ratio of toluene:benzene. The vapour pressure of benzene and toluene at 25° C are 95 and 28 bar respectively.
Find: The mole fraction of toluene vapour.
Solution:
For the equimolar solution of benzene and toluene, the mole fraction of benzene and toluene are 0.5 each.
Total pressure P = Pb + Pr = P(B to O)Xb + P(T to O)Xt
P = 160 * 0.5 + 60 * 0.5
P = 110
The mole fraction of toluene in the vapour phase in contact with an equimolar solution of benzene and toluene.
Yt = Pt/P
Yt = P(T to O) Xt / P
= 60 * 0.5 / 110
= 0.27
Therefore 0.548 is the answer.
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