Question

At certain temperature the solution of benzene and toluene exhibits vapour pressure represented p is equal to 150 x + 65 where x is mole fraction of benzene the vapour pressure of pure benzene is

Answer 1

150 is the vapour pressure of pure benzene.

Explanation:

According to Raoult's law, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the vapor pressure of that component in the pure state.

$p_1=x_1p_1^0$ and $p_2=x_2P_2^0$

where, x = mole fraction

in solution  

$p^0$ = pressure in the pure state

According to Dalton's law, the total pressure is the sum of individual pressures.

$p_{total}=p_1+p_2$

$p_{total}=x_Ap_A^0+x_BP_B^0$

$p_{total}=150\times x+65$

Thus if x is the mole fraction of benzene , 150 is the vapour pressure of pure benzene.

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