Question

a solution containing 10.5 g of alkali is completely neutralizedby 500ml of 0.5 N acid?what is the equivalent mass of alkali
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Answer 1

Answer:

210

Explanation:

equivalent of acid = normality of acid× volume of acid in litres

= 0.5N× 500ml ×10-³l/ml

ml se ml kat jaega

= 0.05 equivalents

for complete neutralization

equivalent of acid= equivalent of base

equivalent weight = weight / equivalent

= 10.5g/0.05 equivalent

= 210 g/equivalent.