a solution containing 2.2 grams of a substance in 125 grams of benzene boils at 80. 66 degree Celsius kb for 1 kg of benzene is 33. 28 degree Celsius/ molal, the molecular weight of the substance shall be
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Answer : The molecular weight of the substance will be, 130.7 g/mol
Explanation :
Formula used for Elevation in boiling point :
or,
where,
= boiling point of solution =
= boiling point of benzene =
= boiling point constant of benzene for 1 kg =
Boiling point constant of benzene for 125 g =
m = molality
i = Van't Hoff factor = 1 (for non-electrolyte)
= mass of solute = 2.2 g
= mass of solvent (benzene) = 125 g
= molar mass of solute = ?
Now put all the given values in the above formula, we get:
Therefore, the molecular weight of the substance will be, 130.7 g/mol
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