Question

A solution containing
is isotonic
806 g/m of areas
with a 5). Solution of
unknown solute the molar mass
g Solute will be
1) 348. a g/mol in 174.5 gmal
is 87.3 gi mal n iV) 34:899 mal
In a
o cellar
002 malcor
1 HX
que "
aqueous esel?
the degree o come
wynay
​

Answer 1

Mglucose = Munknown

\frac{3}{180} \times \frac{1000}{100} = \frac{1}{x} \times \frac{1000}{100}

180

3

×

100

1000

=

x

1

×

100

1000

\frac{3}{180} = \frac{1}{x}

180

3

=

x

1

x = \frac{180}{3}x=

3

180

x=60