Science, asked by shalu5628, 1 year ago

no. of electrons present in 9g of water​

Answers

Answered by brainlyuser16
0

=9/18 ×6 ×10^23 ×10=3× 10^22 electrons


shalu5628: 3*10^3 * 10=3*10^4
Answered by surendrasingh344
0

No.of electron present in 9g of water are 3×10^22

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