Question

a solution contains 10g of Nacl dissolve in 200ml of solution .calculate the molarity of the solution

Answer 1

heyaa !!!

Not sure but hope so it would be correct

#APS☺️☺️

Answer 2

$\underline{\large\huge{\mathfrak{Bonjour!}}}$

According to the question;

Weight of solute(NaCl) in solution = 10 g

Molecular weight of solute (NaCl) = 58.5 g

Volume of solution = 200 mL

$molarity = \frac{weight \: of \: solute}{molecular \: weight \: of \: solute} \times \frac{1}{volume \: of \: solution \: in \: litre} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{10}{58.5} \times \frac{1000}{200} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{10}{58.5} \times 5 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{50}{58.5} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 0.8547M$

Therefore,

Molarity of solution = 0.8547M

$\bf{\mathfrak{Hope \: this \: helps...:)}}$