Question

A solution contains 180 g of glucose (C6H12O6) and 162 g of water. What is the mole fraction of glucose?

Answer 1

Answer:

To find the number of moles of glucose present in 180 g , use the compound's molar mass, which is equal to 180.16 g mol−1 . Now, the mole fraction of glucose is equal to the number of moles of glucose divided by the total number of moles present in solution.

Explanation:

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