Chemistry, asked by jimliboro4365, 28 days ago

A solution contains 25% ethanol and 50% acetic acid by mass. Calculate the mole fraction of each component

Answers

Answered by dineshy9839
1

Answer:

So, mass of water, ethanol and ethanoic acid will be 25 g, 25 g, 50 g respectively.

Moles of water =

25

18

=

1.389

Moles of ethanol =

25

46

=

0.543

Moles of ethanoic acid =

50

60

=

0.833

Total moles = 1.389 + 0.543 + 0.833 = 2.765

Mole fraction of water =

1.389

2.765

=

0.502

Mole fraction of ethanol

=

0.543

2.765

=

0.196

Mole fraction of ethanoic acid

=

0.833

2.765

=

0.301

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