A solution contains 25% ethanol and 50% acetic acid by mass. Calculate the mole fraction of each component
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Answer:
So, mass of water, ethanol and ethanoic acid will be 25 g, 25 g, 50 g respectively.
Moles of water =
25
18
=
1.389
Moles of ethanol =
25
46
=
0.543
Moles of ethanoic acid =
50
60
=
0.833
Total moles = 1.389 + 0.543 + 0.833 = 2.765
Mole fraction of water =
1.389
2.765
=
0.502
Mole fraction of ethanol
=
0.543
2.765
=
0.196
Mole fraction of ethanoic acid
=
0.833
2.765
=
0.301
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