Question

A solution contains 30% of H2SO4 in water. Calculate molality of the solution.

Answer 1

10 percent by volume of H2SO4 means that 10 ml acid in 100 ml solution

volume of H2SO4= 10ml

Volume of water= 90 ml

Density of solution is 1.2 g/cc

mass of aq solution of H2SO4=volume*density= 1.2*100=120gm

Mass of water is= 90*1=90g

Mass of solute i.e. H2SO4= 120-90 = 30g

molality means number of moles of solute present in 1 kg solvent .

Hence molality= number of mole of solute/wt.of solvent in kg

number of mole of solute=30/98=.306

Mass of water is= 90*1=90g=.09kg

molality=.306/.09=3.40

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Answer 2

here is your answer
3.40.
hope it helps