Question

A solution contains 40g of common salt in 320g of water

Answer 1

) Given mass of common salt (NaCl) = 40 g

Molar mass of NaCl = 58.5 g mol-1

Number of moles (n) = Given massMolar mass

n = 4058.5 = 0.683 moles

b) Molar mass of water = 18 g mol-1

Given mass of water = 320 g

18 g of water contains = 6.022×1023 molecules of water

320 g of water contains = 6.022×102318×320 = 107.05×1023 molecules