Question

a solution contains 40g of sulphuric acid in 320 ml of water. calculate concentration by mass/volume percentage, density of sulphuric acid is 1.83 g/ml
NOTE THAT THR SOLVENT IS GIVEN IN VOLUME NOT MASS

Answer 1

Answer:

0.00128 M/ml

Explanation:

Step 1: Since the amount of H₂SO₄ is given in terms of mass, and concentration needs to be calculated, we need to convert the mass into volume.

⇒ Calculating the number of moles of H₂SO₄:

A. Using N = $\frac{g}{M}$ , where N is the number of moles, g is given mass and M is the molar mass.

N = $\frac{40}{98}$

∴ N ≈ 0.4 moles

Step 2: Calculate the final concentration of the solution:

Given volume of water: 320 ml

A. Using M = $\frac{n}{V}$ , where M is the molarity or concentration, n is the number of moles of solute and V is the volume

Total volume of the solution :  341.25 ml [Caculated in the background using: ρ = $\frac{M}{V}$]

∴ M = 0.4/341.25

        ≈ 0.00128 M/ml

∴ Concentration is 0.00128 M/ml

Hope this helps!