A solution contains 55 ml of alcohol mixed with 160 ml of water. Calculate the concentration of the solution.
Answers
Answer:
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Explanation:
volume of solute=55ml
volume of solvent=160ml
total volume = 55+ 160 =215ml
concentration= volume of solute/volume of solution ×100
= 55/215×100
= 25.5%
Answer:This solution contains of this liquid solute (alcohol) mixed with a liquid solvent (water) ,so we have to calculate the concentration of this solution in terms of volume percentage of solute (alcohol ) .(Now, we know that :
Conentration of solution =Volume of soluteVolume of solution ×100
Here ,Volume of solute (alcohol ) =50mL
ANd , Volume of solvent (water ) =150mL
SO , VOlume of solution = Volume Of solute + Volume of Solvent
=50+150
=200mL
Now ,putting these values of volume fo solute and volume of solution in the the above formula we get :
Concentration of sodium =50200×100
=502
=25 per cent (by volume )
thus , the concentration of this alcohol solution is 25 per cent or that it is a 25% alcohol solution (by volume ).
Explanation: