Question

A solution has 15% of suger. Another solution has 5%of suger. Hiw many liters of the 2nd solution must be added to 20 ltr. Of the 1st solution to make a solution of 13% suger?

Answer 1

Answer:

Let x liters of second solution is required to be added

According to the question,

$\frac{15}{100} \times 20 + \frac{1}{20} \times x = (x + 20) \frac{1}{10}$

Solving we get ,

$x = 20l$