A solution has a ph of 4.0. what is the concentration of oh-
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ph = -log [H+]
[H+] = 10^-ph
[H+] = 10^-4
[H+] [OH-] = 10^-14
[OH-] = 10^-14 / 10^-4 = 10^-10
so, concentration of OH- will be 10^-10
[H+] = 10^-ph
[H+] = 10^-4
[H+] [OH-] = 10^-14
[OH-] = 10^-14 / 10^-4 = 10^-10
so, concentration of OH- will be 10^-10
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