Math, asked by pawanraghav, 1 year ago

A Solution has acid: water in the ratio 2:5. If 130 ml of acid and 50 ml of water is added to the solution ,the ration becomes 3:5. What was the quantity of acid and water in the solution originally ?

Answers

Answered by nikolatesla2
3
let quantity be 2x 5x
2x + 130/5x +50 = 3/5
10x +650 = 15x +150
10x-15x = 150-650
-5x = -500
x = 100
quantity of acid in solution = 2×100 = 200ml
quantity of water in solution = 5×100 = 500ml
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