A solution has molarity 2 mol/L. Then find the weight of the solute present in 1ml of the solution. Given that the solute is Urea having molar mass 60 g/mol.
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Molarity = (Weight / GMW) × (1000 / Volume in ml)
Weight of solute = (2 mol/L × 60 g/mol × 1 ml) / 1000 ml/L
= 0.12 g
Weight of solute present in given solution is 0.12 grams.
Weight of solute = (2 mol/L × 60 g/mol × 1 ml) / 1000 ml/L
= 0.12 g
Weight of solute present in given solution is 0.12 grams.
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