A solution is made by dissolving 30g of a non-valatile solute in 90g of water. It has a vapour pressure of 2.8 k Pa at 298K, vapour pressure of pure water is 3.64k Pa. Calculate the molar mass of the solute.
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Answer:
20
Explanation:
m1 = mole of solute = 30/X
m2 = mole of solvent = 90/18 = 5
p1 = initial vapour pressure = 3.64
p2 = final pressure = 2.8
m1 / m2 = (p1 - p2) / p2
Solving, X = 20
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