Question

a solution is made by dissolving 49 gram of H2 S o4 into 50 ml of water the molality of the solution prepared is

Answer 1

250ml water contains 49g. 1000ml contains 196g. So molarity is 196/98=2M...

Answer 2

the formula for Molality is
no. of moles of solute×1000÷amount of solvent is grams
so amount of solute=49 g
molar mass of H2SO4=98gmol^-1
volume of solvent=50ml
density of solvent=1gml^-1
so , amount of solvent=50g
Molality=
$\frac{49}{98} \times \frac{1000}{50}$
=>10 molal