Question

A solution is obtained by mixing 200g of 30% and 300g of 20% solution by weight . What is the percentage of solute in the final solution? (ANS.24%)​

Answer 1

Answer:

solution is the maximun amount of solute that will dissolve in 100g of water at that temperature

Answer 2

So, mass of solute in 200 g of 30 % solution will be = 30 / 100 x 200 = 60 g

So mass of solute in 300 g of 20 % solution will be = 20 / 100 x 300 = 60g

Total solute mass = 120 g

Total solvent mass = 500 g

We know that mass percentage of solute = mass of solute / mass of solution x 100

So mass % = 120 / 500 x 100 = 24%

Thanks.