Question

A solution is obtained by mixing two solutions of same electrolyte with pH = 5 and pH = 3 respectively. The resulting solution has pH

Answer 1

Normality is denoted by N

N1=10^-3

N2=10^-5

N= N1V1 + N2V2/V1+V2

Let their volume V be equal to 1L

N= 10^-3 + 10^-5

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2

On solving,

N=50.5×10^-5

pH is -logN

So pH = 5-log50.5

=5-1.7 =3.3

Answer 2

Answer:

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