Question

a solution is prepared by dissolving 1.9 ×10^-2 kg ammonia in 400 g water calculate elevation of boiling point if Kb for water is 0.52K Kg per mole​

Answer 1

Answer:

The equation for boiling-point elevation looks like this ... as Tb−T∘b. The ebullioscopic constant of water is equal to 0.512∘C kg mol−1 ... b=0.5305 moles559⋅10−3kg=0.949 molal.