Question

A solution is prepared by dissolving 3.65 g of HCl in 500 ml of the solution. Calculate the normality

Answer 1

Given mass of HCl = 3.65 g

Molar mass of HCl = 36.5 g/mol

Basicity of HCl = 1

Now , equivalent of HCl =Molar mass of HCl÷Basicity
= 36.5 ÷ 1 = 36.5 g /equiv

We have to find out the total number of equivalents of HCl.
So, Mass of HCl ÷ Equivalent mass of HCl
= 3.65 ÷ 36.5 = 0.1 equivalent

Given volume of solution = 500 ml = 0.5 l

Normality = Equivalents of HCl ÷ Volume of solution(l)
= 0.1 ÷ 0.5 = 0.2 N

Hence your required answer is 0.2 N

Hope This Helps You!

Answer 2

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