Question

a solution is prepared by dissolving 4 g of NaOH in distilled water to give 200 ml of solution . Molarity of solution is​

Answer 1

Given :

Mass of NaOH = 4g

Volume of solution = 200ml

To Find :

Molarity of the solution.

Solution :

❖ Molarity : Number of moles of solute dissolved in one litre (or one dm³) of solution.

Effect of temperature : Changes with change in temperature

Unit : moles per litre

$\dag\:\underline{\boxed{\bf{\orange{M=\dfrac{Moles\:of\:solute}{Volume\:of\:solution\:in\:L}}}}}$

♦ Moles of NaOH :

Molar mass = 23 + 16 + 1 = 40 g/mol

➙ n = mass / molar mass

➙ n = 4/40

➙ n = 1/10

➙ n = 0.1

♦ Molarity of the solution :

➙ M = n × 1000 / V(ml)

➙ M = 0.1 × 1000/200

➙ M = 0.1 × 5

➙ M = 0.5 mole/litre

Answer 2

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Given :

Mass of NaOH = 4g

Volume of solution = 200ml

To Find :

Molarity of the solution.

Solution :

❖ Molarity : Number of moles of solute dissolved in one litre (or one dm³) of solution.

Effect of temperature : Changes with change in temperature

Unit : moles per litre

Moles = Moles of solute / Volume of solution in L

♦ Moles of NaOH :

Molar mass = 23 + 16 + 1 = 40 g/mol

➙ n = mass / molar mass

➙ n = 4/40

➙ n = 1/10

➙ n = 0.1

♦ Molarity of the solution :

➙ M = n × 1000 / V(ml)

➙ M = 0.1 × 1000/200

➙ M = 0.1 × 5

➙ M = 0.5 mole/litre

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Hope it helps :)