Question

A SOLUTION IS PREPARED
BY
DISSOLVING 45 G of
SUGAR IN 180
t 80 g of water.
CALCULATE THE MASS PERCENTAGE
OF SOLUTE.​

Answer 1

Answer:

20%

Explanation:

total mass=225g

mass of solute=45g

mass of solvent=180g

mass Percentage=mass of solute x100

total mass

=45gx100

225g

=20%

...

Answer 2

Answer:

Question :

A solution is prepared by dissolving 45 g ofsugar in 180 g of water. Calculate the masspercentage of solute.

Answer :

$Mass \: percentage \: \\ \\ = \frac{Mass \: of \: the \: solute}{Mass \: of \: the \: solution} \times 100\\ \\ \\ Given : \: \\ \\ Mass \: of \: solute \: = \: 45 \: grams \\ \\ Mass \: of \: solvent \: (water) = 180 \: grams \\ \\ Mass \: of \: the \: solution \: \\ \\ = Mass \: of \: solute \: + \: Mass \: of \: solvent \: \\ \\ = 180 + 45 = 225 \: grams \\ \\ Mass \: percentage \: = \frac{45}{225} \times 100 \\ \\ = 20 \:$

Therefore, the Mass percentage of solute is 20%.

Tip to do :

• Just substitute and find the value..

Thank you !