Question

a solution is prepared by dissolving 5.64 g of glucose in 16 g of water. calculate the molality.​

Answer 1

Answer:

Molality, m =

Explanation:

Given, Gulcose, C6H12O6 = 5.64 g

And, Water, H2O = 16 g = 16/1000

We know that,

Number of moles of gulcose = Mass given / Molar mass

Moles of gulcose = 5.64/ 180

Molality = Number of moles in solute /

Mass if solution

=> Molality = 5.64 / 180 × 1000 / 16

Molality = 0.52 m

Solved By

Aaditya Singh

Answer 2

Given :

• Mass of Solute = 5.64 g
• Mass of solvent = 60 g

To Find :

• Molality of the solution

Solution :

Molar mass of Glucose $\sf{(C_{6}H_{12}O_{6})}$ = 180 .

We know that :

$\underline{\boxed{ \bf{Molality = \dfrac{Moles \: of \: the \: Solute }{Mass \: of \: the \: solvent \: in \: (kg)} }}} \\ \\ \pink{\longrightarrow \: \small{ \sf{Moles \: of \: the \: Solute = \dfrac{mass \: of \: the \: solute}{molar \: mass \: of \: the \: solute}} }}\\ \\ \pink{\longrightarrow \: \small{ \sf{Moles \: of \: the \: Solute = \dfrac{5.64}{180} }}} \\ \\ \blue{ \longrightarrow \: \small{ \sf{Mass \: of \: the \: solvent \: in \: (kg) = \dfrac{60}{1000} }}} \\ \\ \bullet \: \sf{Molality = \dfrac{ \: \: \: \dfrac{5.64}{180} \: \: \: }{ \: \: \: \dfrac{60}{1000} \: \: \: }} \\ \\ \longrightarrow \: \sf{ Molality = \dfrac{5.64}{180} \times \dfrac{1000}{60} } \\ \\ \longrightarrow \: \sf{ Molality = 0.522 }$

So, the molality of the solution is 0.522 mol/kg .