a solution is prepared by dissolving 5g of urea in 95g of water. what is the mass percent of urea in the solution?
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the weight of solution formed is
5+95=100g
in 100 g solution 5 g urea present
mass precent of urea=5/100×100
=5
therefore 5% urea present in solution
5+95=100g
in 100 g solution 5 g urea present
mass precent of urea=5/100×100
=5
therefore 5% urea present in solution
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