Chemistry, asked by rinkukhattri77901, 1 year ago

A solution is prepared by mixing 8.5 g of ch2cl2 and 11.95 g of chcl3. If vapour pressure of ch2cl2 and chcl3 at 298 k are 415 and 200 mmhg respectively, the mole fraction of chcl3 in vapour form is:

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Answered by shefali927
2

Answer:

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