Question

A Solution of 0.1N KCl offers resistance of 245 ohms .Calculate the specific conductance and the

equivalent conductance of the solution if the cell constant is 0.571cm-¹.​

Answer 1

Answer:

K (specific conductance) =

R

1

(

A

1

)

A

l

=1.29×10

−2

×300=3.87

l/A= cell constant ( cell constant same in both)

In Nacl Sol

n

k=

380

1

(

A

l

)

k=

380

1

×3.87=

380

3.87

=0.0101 onm

−1

cm

2

Explanation:

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